A) \[{{M}^{-2}}{{L}^{2}}{{T}^{-2}}\]
B) \[{{M}^{-1}}{{L}^{3}}{{T}^{-2}}\]
C) \[M{{L}^{-1}}{{T}^{-2}}\]
D) \[M{{L}^{2}}{{T}^{-2}}\]
Correct Answer: B
Solution :
\[F=\frac{G{{m}_{1}}{{m}_{2}}}{{{d}^{2}}}\Rightarrow G=\frac{F{{d}^{2}}}{{{m}_{1}}{{m}_{2}}}\] \[1\,ly=9.46\times {{10}^{15}}\,meter\] \[[G]=\frac{[ML{{T}^{-2}}][{{L}^{2}}]}{[{{M}^{2}}]}=[{{M}^{-1}}{{L}^{3}}{{T}^{-2}}]\]
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