A) \[x=1,\,\,y=1,\,\,z=-1\]
B) \[x=1,\,y=-1,\,z=1\]
C) \[x=-1,\,y=1,\,z=1\]
D) \[x=1,\,y=1,\,z=1\]
Correct Answer: B
Solution :
By substituting the dimension of given quantities \[{{[M{{L}^{-1}}{{T}^{-2}}]}^{x}}{{[M{{T}^{-3}}]}^{y}}{{[L{{T}^{-1}}]}^{z}}={{[MLT]}^{0}}\] By comparing the power of M, L, T in both sides \[x+y=0\] .....(i) \[-x+z=0\] .....(ii) \[-2x-3y-z=0\] ?(iii) The only values of \[x,\,y,\,z\] satisfying (i), (ii) and (iii) corresponds to .You need to login to perform this action.
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