A) \[M{{L}^{2}}{{T}^{-2}}\]
B) \[M{{L}^{2}}{{T}^{-1}}\]
C) \[M{{L}^{-1}}{{T}^{-1}}\]
D) \[MLT\]
Correct Answer: C
Solution :
\[F=-\eta \,.\,A\frac{dv}{dx}\Rightarrow [\eta ]\,=\,[M{{L}^{-1}}{{T}^{-1}}]\]You need to login to perform this action.
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