NEET Physics Mathematical Tools, Units & Dimensions Question Bank Dimensions

  • question_answer
    A spherical body of mass \[m\] and radius \[r\] is allowed to fall in a medium of viscosity \[\eta \].  The time in which the velocity of the body increases from zero to 0.63 times the terminal velocity \[(v)\] is called time constant \[(\tau )\]. Dimensionally \[\tau \] can be represented by                                                          [AIIMS 1987]

    A)    \[\frac{m{{r}^{2}}}{6\pi \eta }\] 

    B)    \[\sqrt{\left( \frac{6\pi mr\eta }{{{g}^{2}}} \right)}\]

    C)      \[\frac{m}{6\pi \eta rv}\]   

    D)             None of the above

    Correct Answer: D

    Solution :

                    Time constant \[\tau =[T]\] and Viscosity \[\eta =[M{{L}^{-1}}{{T}^{-1}}]\] For options and dimensions are not matching with time constant.


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