A) \[M{{L}^{-1}}{{T}^{-1}}\]
B) \[M{{T}^{-1}}\]
C) \[ML{{T}^{-2}}\]
D) \[M{{L}^{-3}}\]
Correct Answer: A
Solution :
\[\eta =\frac{F}{av}=\frac{[ML{{T}^{-2}}]}{[L]\,[L{{T}^{-1}}]}=[M{{L}^{-1}}{{T}^{-1}}]\]You need to login to perform this action.
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