A) \[{{v}^{2}}/rg\]
B) \[{{v}^{2}}r/g\]
C) \[{{v}^{2}}g/r\]
D) \[{{v}^{2}}rg\]
Correct Answer: A
Solution :
Angle of banking : \[\tan \theta =\frac{{{v}^{2}}}{rg}\]. i.e. \[\frac{{{v}^{2}}}{rg}\]is dimensionless.You need to login to perform this action.
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