A) \[[M{{L}^{2}}{{T}^{-2}}]\]
B) \[[M{{L}^{-1}}{{T}^{-1}}]\]
C) \[[M{{L}^{-2}}{{T}^{-2}}]\]
D) \[[{{M}^{0}}{{L}^{0}}{{T}^{0}}]\]
Correct Answer: B
Solution :
\[F=-\eta A\frac{\Delta v}{\Delta z}\Rightarrow [\eta ]=[M{{L}^{-1}}{{T}^{-1}}]\] As \[F=[ML{{T}^{-2}}],\,\,A=[{{L}^{2}}],\,\frac{\Delta v}{\Delta z}=[{{T}^{-1}}]\]You need to login to perform this action.
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