A) \[{{M}^{0}}{{L}^{0}}{{T}^{0}}\]
B) \[{{M}^{0}}{{L}^{0}}{{T}^{2}}\]
C) \[{{M}^{2}}{{L}^{0}}{{T}^{2}}\]
D) \[ML{{T}^{2}}\]
Correct Answer: B
Solution :
\[f=\frac{1}{2\pi \sqrt{LC}}\Rightarrow LC=\frac{1}{{{f}^{2}}}=[{{M}^{0}}{{L}^{0}}{{T}^{2}}]\]
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