A) \[{{A}^{-2}}{{M}^{1}}{{L}^{1}}{{T}^{-2}}\]
B) \[ML{{T}^{-2}}\]
C) \[M{{L}^{0}}{{T}^{-1}}\]
D) \[{{A}^{-1}}ML{{T}^{2}}\]
Correct Answer: A
Solution :
\[F=\frac{{{\mu }_{0}}}{4\pi }\,\frac{2{{I}_{1}}{{I}_{2}}l}{r}\] \[\Rightarrow \] \[{{\mu }_{0}}=[F]\,{{[A]}^{-2}}=[ML{{T}^{-2}}{{A}^{-2}}]\]
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