A) \[M{{L}^{2}}{{T}^{-2}}\]
B) \[{{M}^{2}}L{{T}^{-1}}\]
C) \[M{{L}^{2}}{{T}^{-1}}\]
D) \[M{{L}^{3}}{{T}^{-1}}\]
Correct Answer: A
Solution :
Kinetic energy = \[\frac{1}{2}m{{v}^{2}}=M{{[L{{T}^{-1}}]}^{2}}=[M{{L}^{2}}{{T}^{-2}}]\]
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