A) \[x=\frac{1}{2},\,y=\frac{1}{2}\]
B) \[x=-\frac{1}{2},\,y=-\frac{1}{2}\]
C) \[x=\frac{1}{2},\,y=-\frac{1}{2}\]
D) \[x=-\frac{1}{2},\,y=\frac{1}{2}\]
Correct Answer: D
Solution :
By putting the dimensions of each quantity both the sides we get \[[{{T}^{-1}}]={{[M]}^{x}}{{[M{{T}^{-2}}]}^{y}}\] Now comparing the dimensions of quantities in both sides we get \[x+y=0\ \text{and }\,2y=1\] \[\therefore \] \[x=-\frac{1}{2},\,\,y=\frac{1}{2}\]You need to login to perform this action.
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