A) \[C{{H}_{3}}-CH=C{{H}_{2}}+HBr\to C{{H}_{3}}-\underset{Br\ }{\mathop{\underset{|}{\mathop{C}}\,H}}\,-C{{H}_{3}}\]
B) \[C{{H}_{3}}-CHO+HCN\to C{{H}_{3}}-CH<\begin{matrix} CN \\ OH \\ \end{matrix}\]
C) \[C{{H}_{3}}-CH=C{{H}_{2}}+HBr\to C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-Br\]
D) \[C{{H}_{3}}CHO+N{{H}_{2}}OH\xrightarrow{{{H}^{+}}}C{{H}_{3}}-CH=N-OH\]
Correct Answer: C
Solution :
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