A) 41.8 debye
B) 4.18 debye
C) 4.8 debye
D) 0.48 debye
Correct Answer: C
Solution :
Given ionic charge \[=4.8\times {{10}^{-10}}\]e.s.u. and ionic distance \[=1A{}^\circ ={{10}^{-8}}cm\] we know that dipole moment = ionic charge × ionic distance \[=4.8\times {{10}^{-10}}\times {{10}^{-8}}\] \[=4.8\times {{10}^{-8}}\]e.s.u. per cm \[=4.8\]debye.You need to login to perform this action.
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