A) 17
B) 83
C) 50
D) Zero
E) 90
Correct Answer: A
Solution :
% of ionic character =\[\frac{\text{Experimental value of dipole moment}}{\text{Expected value of dipole moment}}\] \[=\frac{1.03}{6.12}\times 100=16.83%\approx 17%\]You need to login to perform this action.
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