A) 25 metres
B) 50 Metres
C) 115 Meters
D) 35 Metres
Correct Answer: D
Solution :
The movements of Deepak are as shown in fig. Clearly, FB = DC = 40 m. \[\therefore \]Deepak's distance from the starting point A \[=\left( AB-EB \right)=\left( 75-40 \right)m=35m.\]You need to login to perform this action.
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