A) p / 3
B) p / 6
C) p / 2
D) p
Correct Answer: A
Solution :
\[x=a\sin \left( \omega t+\frac{\pi }{6} \right)\]and \[x'=a\cos \omega t=a\sin \,\left( \omega \,t+\frac{\pi }{2} \right)\] \[\therefore \] \[\Delta \varphi =\left( \omega t+\frac{\pi }{2} \right)-\left( \omega t+\frac{\pi }{6} \right)=\frac{\pi }{3}\]You need to login to perform this action.
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