A) \[10\sqrt{2}m\]
B) \[10m\]
C) \[\frac{10}{\sqrt{2}}m\]
D) \[10\times 2m\]
Correct Answer: A
Solution :
\[\vec{r}=x\hat{i}+y\hat{j}+z\hat{k}\] \[\therefore \]\[r=\sqrt{{{x}^{2}}+{{y}^{2}}+{{z}^{2}}}\] r\[=\sqrt{{{6}^{2}}+{{8}^{2}}+{{10}^{2}}}=10\sqrt{2}\ m\]
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