A) \[{{a}^{2}}+{{b}^{2}}={{p}^{2}}\]
B) \[{{a}^{2}}+{{b}^{2}}=\frac{1}{{{p}^{2}}}\]
C) \[\frac{1}{{{a}^{2}}}+\frac{1}{{{b}^{2}}}=\frac{2}{{{p}^{2}}}\]
D) \[\frac{1}{{{a}^{2}}}+\frac{1}{{{b}^{2}}}=\frac{1}{{{p}^{2}}}\]
Correct Answer: D
Solution :
\[p=\frac{ab}{\sqrt{{{a}^{2}}+{{b}^{2}}}}\] or \[\frac{{{a}^{2}}+{{b}^{2}}}{{{a}^{2}}{{b}^{2}}}=\frac{1}{{{p}^{2}}}\Rightarrow \frac{1}{{{a}^{2}}}+\frac{1}{{{b}^{2}}}=\frac{1}{{{p}^{2}}}\].You need to login to perform this action.
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