A) 400m
B) 150m
C) 300m
D) 250m
Correct Answer: D
Solution :
Distance travelled by the 1st car in 15 seconds \[=OA=\left( 36\times \frac{5}{18} \right)\,\times 15\,m=150m\] Distance travelled by the 2nd car in 15 seconds \[=OB=\left( 48\times \frac{5}{18} \right)\,\times 15\,m=200\,m\] \[\therefore \] Distance between them after 15 seconds \[=AB=\sqrt{O{{A}^{2}}+O{{B}^{2}}}\,=\sqrt{{{150}^{2}}+{{200}^{2}}}\] \[=\sqrt{22500+40000}\] \[=\sqrt{62500}=\,250\,m\].You need to login to perform this action.
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