A) \[1.15\times {{10}^{7}}cm/\sec \]
B) \[1.15\times {{10}^{7}}m/\sec \]
C) \[1.15\times {{10}^{7}}km/\sec \]
D) 1.15 km/sec
Correct Answer: B
Solution :
\[\Delta \lambda =5200-5000=200{AA}\] Now \[\frac{\Delta \lambda }{\lambda '}=\frac{v}{c}\Rightarrow v=\frac{c\Delta \lambda }{\lambda '}=\frac{3\times {{10}^{8}}\times 200}{5000}\] \[=1.2\times {{10}^{7}}m/\sec \approx 1.15\times {{10}^{7}}m/\sec \]
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