A) 5%
B) 20%
C) Zero
D) 0.5%
Correct Answer: B
Solution :
When observer moves towards stationary source then apparent frequency \[n'=\left[ \frac{v+{{v}_{O}}}{v} \right]\,n\]\[=\left[ \frac{v+v/5}{v} \right]\,n\]\[=\frac{6}{5}n=1.2n\] Increment in frequency = 0.2 n so percentage change in frequency = \[\frac{0.2n}{n}\times 100\]= 20%.You need to login to perform this action.
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