A) 540 m/s
B) 270 m/s
C) 85 m/s
D) 52.5 m/s
Correct Answer: C
Solution :
When engine approaches towards observer \[n'=n\,\left( \frac{v}{v-{{v}_{s}}} \right)\] when engine going away from observer \[{n}''=\left( \frac{v}{v+{{v}_{S}}} \right)n\] \[\therefore \] \[\frac{n'}{n''}=\frac{v+{{v}_{s}}}{v-{{v}_{s}}}\Rightarrow \frac{5}{3}=\frac{340+{{v}_{s}}}{340-{{v}_{s}}}\Rightarrow {{v}_{s}}=85\]\[m/s\].You need to login to perform this action.
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