A) 1000 Hz
B) 1066 Hz
C) 941 Hz
D) 352 Hz
Correct Answer: C
Solution :
For source vS = \[r\omega =0.70\times 2\pi \times 5=22\]m/sec Minimum frequency is heard when the source is receding the man. It is given by \[{{n}_{\min }}=n\frac{v}{v+{{v}_{s}}}\] = \[1000\times \frac{352}{352+22}=941\]\[Hz\]You need to login to perform this action.
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