A) \[\frac{v}{2}\]
B) 2v
C) \[\frac{v}{4}\]
D) v
Correct Answer: D
Solution :
Frequency is decreasing (becomes half), it means source is going away from the observes. In this case frequency observed by the observer is \[{n}'=n\left( \frac{v}{v+{{v}_{s}}} \right)\] Þ \[\frac{n}{2}=n\,\left( \frac{v}{v+{{v}_{S}}} \right)\] Þ\[{{v}_{S}}=v\]You need to login to perform this action.
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