A) Electron
B) Proton
C) \[C{{O}_{2}}\] molecule
D) \[S{{O}_{2}}\] molecule
Correct Answer: D
Solution :
\[\lambda =\frac{h}{mv}.\] For same velocity \[\lambda \propto \frac{1}{m}\]. \[S{{O}_{2}}\] molecule has least wavelength because their molecular mass is high.You need to login to perform this action.
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