Answer:
de -Broglie wavelength, \[\lambda =\frac{h}{m\upsilon }\] As the mass of a proton is 1836 times that of an electron, so for the same speed, the wavelength of proton beam will be\[\frac{1}{1836}\]times that of an electron beam. But resolving power of a microscope \[\propto \frac{1}{\text{wavelength}}.\] Hence the resolving power of a proton microscope will be 1836 times that of an electron microscope.
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