A) \[7\times {{10}^{-5}}tesla\]
B) \[6\times {{10}^{-5}}tesla\]
C) \[5\times {{10}^{-5}}tesla\]
D) \[9.2\times {{10}^{-5}}tesla\]
Correct Answer: D
Solution :
From the relation \[{{B}_{V}}=I\sin \varphi \] \[I=\frac{V}{\sin \varphi }=\frac{6\times {{10}^{-5}}}{\sin {{40.6}^{o}}}=\frac{6\times {{10}^{-5}}}{0.65}=9.2\times {{10}^{-5}}\]tesla
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