A) 4 : 1
B) 1 : 2
C) 2 : 1
D) 1 : 8
Correct Answer: D
Solution :
At broad side-on position \[B=\frac{M}{{{d}^{3}}}\] \[\therefore \,\frac{{{M}_{1}}}{d_{1}^{3}}=\frac{{{M}_{2}}}{d_{2}^{3}}or\frac{{{M}_{1}}}{{{r}^{3}}}=\frac{{{M}_{2}}}{8{{r}^{3}}}or\frac{{{M}_{1}}}{{{M}_{2}}}=\frac{{{r}^{3}}}{8{{r}^{3}}}=\frac{1}{8}\]You need to login to perform this action.
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