question_answer

The horizontal component of the earth's magnetic field is 0.22 Gauss and total magnetic field is 0.4 Gauss. The angle of dip. is                                                                        [MP PMT 2004]

A)            \[{{\tan }^{-1}}\,(1)\]           

B)            \[{{\tan }^{-1\,}}(\infty )\]

C)            \[{{\tan }^{-1\,}}(1.518)\]   

D)            \[{{\tan }^{-1\,}}(\pi )\]

Correct Answer: C

Solution :

           By using \[{{B}_{H}}=B\cos \varphi \] Þ \[\cos \varphi =\frac{{{B}_{H}}}{B}=\frac{0.22}{0.4}\] Þ \[\tan \varphi =\frac{\sqrt{{{(0.4)}^{2}}-{{(0.22)}^{2}}}}{0.22}\] Þ \[\varphi ={{\tan }^{-1}}(1.518)\]