A) \[{{\tan }^{-1}}\left( \frac{{{H}_{0}}}{H} \right)\]
B) \[{{\tan }^{-1}}\left( \frac{H}{{{H}_{0}}} \right)\]
C) \[\cos e{{c}^{-1}}\left( \frac{H}{{{H}_{0}}} \right)\]
D) \[{{\cot }^{-1}}\left( \frac{{{H}_{0}}}{H} \right)\]
Correct Answer: A
Solution :
In given case H and H0 are perpendicular to each other. From figure \[\tan \theta =\frac{{{H}_{0}}}{H}\] Þ \[\theta ={{\tan }^{-1}}\left( \frac{{{H}_{0}}}{H} \right)\]You need to login to perform this action.
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