A) \[60{}^\circ \]
B) \[45{}^\circ \]
C) \[90{}^\circ \]
D) \[\begin{align} & 2rH \\ & {{\mu }_{0}}N \\ \end{align}\]
Correct Answer: D
Solution :
\[{{B}_{H}}=\sqrt{3}\ {{B}_{V}},\]also \[\tan \theta =\frac{{{B}_{V}}}{{{B}_{H}}}=\frac{1}{\sqrt{3}}\Rightarrow \theta ={{30}^{o}}\]
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