JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Electric Conduction Ohms and Resistance

  • question_answer
    Current of 4.8 amperes is flowing through a conductor. The number of electrons per second will be        [CPMT 1986]

    A)                    \[3\times {{10}^{19}}\]

    B)            \[7.68\times {{10}^{21}}\]

    C)                    \[7.68\times {{10}^{20}}\]                                          

    D)            \[3\times {{10}^{20}}\]

    Correct Answer: A

    Solution :

       Number of electrons flowing per second \[\frac{n}{t}=\frac{i}{e}\]\[=4.8/1.6\times {{10}^{-19}}=3\times {{10}^{19}}\]


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