A) v
B) \[\frac{v}{2}\]
C) \[\frac{v}{4}\]
D) \[\frac{v}{8}\]
Correct Answer: B
Solution :
\[{{v}_{d}}=\frac{i}{ne\pi {{r}^{2}}}\Rightarrow {{v}_{d}}\propto \frac{i}{{{r}^{2}}}\Rightarrow \frac{v}{v'}=\frac{{{i}_{1}}}{{{i}_{2}}}\times {{\left( \frac{{{r}_{2}}}{{{r}_{1}}} \right)}^{2}}\]\[\Rightarrow \,\,v'=\frac{v}{2}\].
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