A) \[\frac{9R}{16}\]
B) \[\frac{16R}{9}\]
C) \[\frac{81R}{256}\]
D) \[\frac{256R}{81}\]
Correct Answer: D
Solution :
\[\frac{{{R}_{1}}}{{{R}_{2}}}={{\left( \frac{{{r}_{2}}}{{{r}_{1}}} \right)}^{4}}\]Þ \[\frac{R}{{{R}_{2}}}={{\left( \frac{3r/4}{r} \right)}^{4}}=\frac{81}{256}={{R}_{2}}=\frac{256}{81}R\]
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