A) 16 R
B) 3 R
C) 2R
D) R
Correct Answer: A
Solution :
In stretching, \[\frac{{{R}_{2}}}{{{R}_{1}}}={{\left( \frac{{{r}_{1}}}{{{r}_{2}}} \right)}^{4}}\]\[\Rightarrow \,\frac{{{R}_{2}}}{R}={{\left( \frac{2}{1} \right)}^{4}}\]\[\Rightarrow \,{{R}_{2}}=16R\]
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