A) \[1\times {{10}^{19}}m/s\]
B) \[5\times {{10}^{10}}m/s\]
C) \[2\times {{10}^{4}}m/s\]
D) \[8\times {{10}^{3}}m/s\]
Correct Answer: C
Solution :
By using \[{{v}_{d}}=\frac{i}{neA}=\frac{100}{{{10}^{28}}\times 1.6\times {{10}^{-19}}\times \frac{\pi }{4}\times {{(0.02)}^{2}}}\] \[=2\times {{10}^{-4}}\,m/\sec \]
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