A) 10%
B) 25%
C) 21%
D) 9%
Correct Answer: C
Solution :
\[\frac{{{R}_{1}}}{{{R}_{2}}}={{\left( \frac{{{l}_{1}}}{{{l}_{2}}} \right)}^{2}},\] If \[{{l}_{1}}=100\] then l2 = 110 Þ \[\frac{{{R}_{1}}}{{{R}_{2}}}={{\left( \frac{100}{110} \right)}^{2}}\] Þ \[{{R}_{2}}=1.21\,{{R}_{1}}\] % change \[\frac{{{R}_{2}}-{{R}_{1}}}{{{R}_{1}}}\times 100=21%\]
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