A) \[v/4\]
B) \[v/2\]
C) \[v\]
D) \[4v\]
Correct Answer: C
Solution :
\[{{v}_{d}}=\frac{J}{ne}\] \[\Rightarrow \] \[{{v}_{d}}\propto J\] (current density) \[{{J}_{1}}=\frac{i}{A}\] and \[{{J}_{2}}=\frac{2i}{2A}=\frac{i}{A}={{J}_{1}}\]; \ \[{{({{v}_{d}})}_{1}}={{({{v}_{d}})}_{2}}=v\]
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