A) \[2R\]
B) \[R\]
C) \[R/2\]
D) \[R/4\]
Correct Answer: B
Solution :
\[R\propto \frac{l}{A}\propto \frac{l}{{{d}^{2}}}\] Þ \[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{{{l}_{1}}}{{{l}_{2}}}\times \,{{\left( \frac{{{d}_{2}}}{{{d}_{1}}} \right)}^{2}}=\frac{L}{4L}\,{{\left( \frac{2d}{d} \right)}^{2}}=1\] Þ \[{{R}_{2}}={{R}_{1}}=R.\]
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