A) \[100{}^\circ C\]
B) \[137{}^\circ C\]
C) \[167{}^\circ C\]
D) \[200{}^\circ C\]
Correct Answer: C
Solution :
\[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{(1+\alpha {{t}_{1}})}{(1+\alpha {{t}_{2}})}\Rightarrow \frac{50}{76.8}=\frac{(1+3.92\times {{10}^{-3}}\times 20)}{(1+3.92\times {{10}^{-3}}t)}\] \[\Rightarrow t=167{}^\circ C\]
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