A) A has more loss of weight
B) B has more loss of weight
C) Both have same loss of weight
D) Loss of weight will be in the ratio \[1:2\]
Correct Answer: A
Solution :
\[R=\rho \frac{l}{A}\Rightarrow \frac{{{R}_{1}}}{{{R}_{2}}}=\frac{{{A}_{2}}}{{{A}_{1}}}(\rho ,L\]constant) \[\Rightarrow \frac{{{A}_{1}}}{{{A}_{2}}}=\frac{{{R}_{2}}}{{{R}_{1}}}=2\] Now, when a body dipped in water, loss of weight \[=V{{\sigma }_{L}}g=AL{{\sigma }_{L}}g\] So, \[\frac{{{\text{(Loss of weight)}}_{\text{1}}}}{{{\text{(Loss of wight)}}_{\text{2}}}}=\frac{{{A}_{1}}}{{{A}_{2}}}=2;\]so A has more loss of weight.
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