A) \[\text{1}{{0}^{\text{11}}}\]
B) \[\text{1}{{0}^{\text{16}}}\]
C) \[\text{1}{{0}^{\text{19}}}\]
D) \[\text{1}{{0}^{\text{15}}}\]
Correct Answer: B
Solution :
\[i=\frac{ne}{t}\]Þ \[n=\frac{it}{e}=\frac{1.6\times {{10}^{-3}}\times 1}{1.6\times {{10}^{-19}}}={{10}^{16}}\].
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