A) \[5.1\times {{10}^{-3}}\] amp
B) \[6.8\times {{10}^{-3}}\] amp
C) \[1.1\times {{10}^{-3}}\] amp
D) \[2.2\times {{10}^{-3}}\] amp
Correct Answer: C
Solution :
\[i=e\nu =1.6\times {{10}^{-19}}\times 6.8\times {{10}^{15}}=1.1\times {{10}^{-3}}amp.\]
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