A) \[1.25\text{ }\times ~{{10}^{3}}m/s\]
B) \[2.50\text{ }\times ~{{10}^{-3}}m/s\]
C) \[25.0\text{ }\times ~{{10}^{-3}}m/s\]
D) \[250\text{ }\times ~{{10}^{-3}}m/s\]
Correct Answer: B
Solution :
\[{{V}_{d}}=\frac{i}{neA}=\frac{40}{{{10}^{29}}\times {{10}^{-6}}\times 1.6\times {{10}^{-19}}}\] = \[2.5\times {{10}^{-3}}m/sec\].You need to login to perform this action.
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