JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Electric Conduction, Ohm's and Resistance

  • question_answer
    The temperature coefficient of resistance for a wire is \[0.00125/{}^\circ C\]. At 300K its resistance is 1 ohm. The temperature at which the resistance becomes 2 ohm is                                 [IIT 1980; MP PET 2002; KCET 2003; MP PMT 2001; Orissa JEE 2002]

    A)                    1154 K

    B)                                      1100 K

    C)                    1400 K                             

    D)            1127 K

    Correct Answer: D

    Solution :

                 \[\frac{{{\rho }_{1}}}{{{\rho }_{2}}}=\frac{(1+\alpha {{t}_{1}})}{(1+\alpha {{t}_{2}})}\Rightarrow \frac{1}{2}=\frac{(1+0.00125\times 27)}{(1+0.00125\times t)}\]            \[\Rightarrow t=854{}^\circ C\Rightarrow T=1127K\]


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