JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Electric Conduction Ohms and Resistance

  • question_answer
    There is a current of 40 ampere in a wire of \[{{10}^{-6}}\,{{m}^{2}}\] area of cross-section.  If the number of free electron per \[{{m}^{3}}\] is \[{{10}^{29}}\],  then the drift velocity will be            [Pb. PMT 2001]

    A)            \[1.25\text{ }\times ~{{10}^{3}}m/s\]

    B)                                      \[2.50\text{  }\times ~{{10}^{-3}}m/s\]

    C)            \[25.0\text{  }\times ~{{10}^{-3}}m/s\]

    D)                                      \[250\text{  }\times ~{{10}^{-3}}m/s\]

    Correct Answer: B

    Solution :

                 \[{{V}_{d}}=\frac{i}{neA}=\frac{40}{{{10}^{29}}\times {{10}^{-6}}\times 1.6\times {{10}^{-19}}}\]  = \[2.5\times {{10}^{-3}}m/sec\].


You need to login to perform this action.
You will be redirected in 3 sec spinner