A) 160 W
B) 80 W
C) 40 W
D) 20 W
Correct Answer: A
Solution :
\[\frac{{{R}_{1}}}{{{R}_{2}}}={{\left( \frac{{{l}_{1}}}{{{l}_{2}}} \right)}^{2}}\]\[\Rightarrow \,\,\,\frac{10}{{{R}_{2}}}={{\left( \frac{5}{20} \right)}^{2}}=\frac{1}{16}={{R}_{2}}=160\Omega \].
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