A) \[pE\]
B) \[+\,2pE\]
C) \[-2pE\]
D) Zero
Correct Answer: D
Solution :
Work done \[=\int_{\,90}^{\,270}{pE\sin \theta \,d\theta }=[\,-\,pE\cos \theta ]_{\,90}^{\,270}=0\]You need to login to perform this action.
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