A) \[{{p}^{-1}}\] and \[{{r}^{-2}}\]
B) \[p\] and \[{{r}^{-2}}\]
C) \[{{p}^{-1}}\] and \[{{r}^{-2}}\]
D) \[p\] and \[{{r}^{-3}}\]
Correct Answer: D
Solution :
\[{{E}_{equatorial}}=\frac{kp}{{{r}^{3}}}\] i.e. \[E\propto p\] and \[E\propto {{r}^{-3}}\]You need to login to perform this action.
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