A) \[6.25\times {{10}^{7}}\] N/C
B) \[9.28\times {{10}^{7}}\] N/C
C) \[13.1\times {{11}^{11}}\] N/C
D) \[20.5\times {{10}^{7}}\] N/C
Correct Answer: A
Solution :
By using \[E=9\times {{10}^{9}}.\frac{2p\,r}{{{({{r}^{2}}-{{l}^{2}})}^{2}}};\] where \[p=(\text{5}00\times \text{1}{{0}^{\text{6}}})\times (\text{1}0\times \text{1}{{0}^{\text{2}}})=\text{5}\times \text{1}{{0}^{\text{5}}}\], r = 25 cm = 0.25 m, l = 5 cm = 0.05 m \[E=\frac{9\times {{10}^{9}}\times 2\times 5\times {{10}^{-5}}\times 0.25}{{{\{{{(0.25)}^{2}}-{{(0.05)}^{2}}\}}^{2}}}\] \[=6.25\times {{10}^{7}}N/C\]You need to login to perform this action.
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